Monday, May 11, 2026

Calculating curvature


Curvature is conceptually easy however often troublesome to calculate. For a stage set curve f(xy) = c, reminiscent of within the earlier couple posts, the equation for curvature is

Even when f has a reasonably easy expression, the expression for κ could be sophisticated.

If we outline

f(x, y) = y^3 - 3 x^2 - 3 y^2 - 3 x^2 y

then the extent set of f(xy) = c is an equilateral triangle when c = −4. The extent units are smoothed triangles for −4 < c < 0.

The curvature of those stage units at any level is given by

frac2 (y+1) left((y-2)^2-3 x^2right) left(x^2+y^2right)right{left(x^4+2 x^2 (y (y+6)+2)+(y-2)^2 y^2right)^{3/2}}

Simplification

However there’s one occasion through which curvature is straightforward to calculate. For the graph of a operate g(x) = y, the curvature is roughly absolutely the worth of the second by-product of g, offered the primary by-product is small.

 kappa = frac{|g^{primeprime}(x)|}{(1 + g^prime(x))^{3/2}} approx |g^{primeprime}(x)|

At an area most or native minimal of g(x) the approximation is actual as a result of the primary by-product is zero.

Max and min curvature of smoothed triangles

Which means within the instance above, we are able to calculate the utmost and minimal curvature of the extent units. The utmost curvature happens within the corners and the minimal happens in the midst of the edges. By symmetry there are three maxima and three minima, however we are able to take those equivalent to x = 0 for comfort. There we discover the curvature is solely

|6 + 6y|

When x = 0, now we have

f(x,y) = c = y^3 - 3y^2

and so the utmost and minimal curvature are the 2 roots of the cubic equation for y that lie within the interval [−1, 2]. (There’s one other root better than 2.)

For instance, when c = −3, the roots are 0.8794, 1.3473, and a pair of.5321. The primary root corresponds to the minimal curvature, the second to the utmost, and the third is outdoors our area of curiosity. It follows that the minimal curvature is 0.7237 and the utmost is 14.0838.

When c = −1 the minimal and most curvature are 2.80747 and 9.91622 respectively,

Since c = −4 corresponds to the triangle, the minimal curvature is 0 and the utmost is infinite. As c will increase, the minimal and most curvature come collectively as a result of the extent set is turning into extra spherical.

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